factorise x cube + 64 y cube
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x³+64y³
x³+(4y)³
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Using identity
a³+b³=(a+b)(a²-ab+b²)
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x³+(4y)³=(x+4y)(x²-4xy+16y²)
x³+(4y)³
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Using identity
a³+b³=(a+b)(a²-ab+b²)
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x³+(4y)³=(x+4y)(x²-4xy+16y²)
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