factorise x( cube) + 6x ( square) +11x + 6
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[tex] x^{3} + 6x^{2} +11x+6
= x^{2} (x+6)+11(x+6)
=( x^{2} +11)(x+6)
[/tex]
abbadshah:
wrong
x^2(x+6)+1(11x+6)
Sorry, I read the question wrong,here is the answer......factorizing left side of equation gives (x + 3)(x + 2)(x + 1) = 0........hence,,x=-1 or x=-2 or x=-3
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