factorise x cube minus 12 x square + 47 x minus 60
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Ohh sorry friend question was right
Step-by-step explanation:
x^3-12x^2+47x-60
=x^3-3x^2-9x^2+27x+20x-60
= x^2(x-3)-9x(x-3)+20(x-3)
=(x-3)(x^2-9x+20)
=(x-3)(x^2-5x-4x+20)
=(x-3){x(x-5)-4(x-5)}
=(x-3)(x-5)(x-4)
factorisation is (x-3)(x-4)(x-5)
Sorry for the first.........
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