Question

factorise x cube minus 2 x square y + 3 x y squared minus 6 y cube​

Answer 1

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Answer 2

Given : x

3

−2x

2

y+3xy

2

−6y

3

By taking x

2

as common in the first two term and 3y

2

as common in the second two term

x

3

−2x

2

y+3xy

2

−6y

3

=x

2

(x−2y)+3y

2

(x−2y)

So we get,

x

3

−2x

2

y+3xy

2

−6y

3

=(x−2y)(x

2

+3y

2

)