factorise x cube minus 23 x square + 142 X - 120
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Answer:
x^3 - 23x^2 + 142x - 120
The common factor is (x-1)
so, x^2(x-1) -22x(x-1) +120(x-1)
or, (x-1) (x^2 - 22x + 120)
or, (x-1) (x^2 -10x -12x + 120)
or, (x-1) [x(x-10) -12(x-10) ]
or, (x-1) (x-10) (x-12)
this is the solution of your question
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