Question

In the adjoining figure, M
is the centre of the circle and
seg AB is a diameter
seg MS perpendicular chord AD
seg MT perpendicular chord AC
angle DAB congruent angle CAB
Prove that : chord AD chord AC.​

Answer 1

Answer:

the answer is shown above.

Brainliest plz

Answer 2

Given: seg AB is a diameter ,seg MS perpendicular chord AD  ,seg MT perpendicular chord AC

To prove : AC = AD

Explanation:

Since , seg MS perpendicular chord AD

seg MT perpendicular chord AC

AT = TC and AS = SD ..(1)

now in triangle ATS and ASM

AM = MA (common)

$\angle SAM = \angle MAT \\\\\angle MSA = \angle MTA = 90^\circ$ (given )

thus

by ASA congruency

$\bigtriangleup SAM \cong \bigtriangleup MAT$

THUS

AT = AS (by CPCT)

multiply by 2 both sides

2AT = 2AS

AT+ AT = AS + AS

AT + TC = AS+ SD  from 1

AC = AD

hence proved

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