factorise x cube minus 23 x square + 142 X - 120
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Answer:
(x - 1)(x - 10)(x - 12)
Step-by-step explanation:
By trial and error we can see that x=1 is a factor of the above equation.
So, x-1 is a factor of x^3 - 23x^2 + 142x - 120
Divide the equation by (x-1)
We get the quotient: x^2 - 22x + 120
On factorising this equation, we get
(x - 10)(x - 12)
Therefore the factors of the above given cubic equation are (x - 1)(x - 10)(x - 12)
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