Question

factorise x cube minus 5 x square - x + 5 ​

Answer 1

${\huge{\orange{\bf{HOLA!!}}}}$

x³-5x²-x+5

using grouping method

x²(x-5)-1(x-5)

(x²-1)(x-5)

{x²-1} can be written as (x+1)(x-1) using the identity (a+b)(a-b)=a²-b²

=(x+1)(x-1)(x-5)

Factors are:-

• x+1
• x-1
• x-5

Hope it helps you....

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Answer 2

Hey !

Factorisation

We know ,

a² - b² = ( a + b ) ( a - b )

=> x³ - 5x² - x + 5

=> x² ( x - 5 ) - 1 ( x + 5 )

=> ( x² - 1 ) ( x + 5 )

=> ( x + 1 ) ( x - 1 ) ( x + 5 ) Ans

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