Question

Factorise x cube - x.

Answer 1

$Given \:x^{3} - x \\= x(x^{2} - 1) \\= x(x^{2} - 1^{2}) \\= x(x+1)(x-1)$

$\boxed { \pink {since, a^{2} - b^{2} = (a+b)(a-b)}}$

Therefore.,

$\red { Factors \: of \:x^{3} - x }\\\green{=x(x+1)(x-1) }$

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Answer 2

Answer:

x (x+1) (x-1)

Step-by-step explanation:

x³ - x
= x (x² - 1)
= x (x²-1²)
= x (x+1) (x-1)