Question

The order of screening effect of electrons of s, p, d and f orbitals of a given
shell of an atom on its outer shell electrons is:
(i) s > p > d > f
(ii) f > d > p > s
(iii) p < d < s > f
(iv) f > p > s > d


NCERT Class XI
Chemistry - Exemplar Problems

Chapter 3. Classification of Elements and Periodicity in Properties

Answer 1

s<p<d<f
so we can write it f>d>p>s
so correct is (ii)

Answer 2

The order of screening effect of electrons of s, p, d and f orbitals of a given shell of an atom on its outer shell electrons s > p > d > f.

Option (i)

Explanation:

• S has the greatest effect to reduce the force of attraction between the outermost electron and nucleus due to its effective charge density followed by p > d > f. According to orbital order, S orbital is closest to the nucleus followed by the P orbital, D orbital and finally the F orbital.
• So According to the screening effect,  S orbital being close to the nucleus lacks screening from any other orbital as it is the first and the closest orbital. P orbital electrons are loosely bound with greater size than s block elements as they undergo screening from S orbital electrons.
• Similarly, D orbital electrons undergo screening from S and P block orbitals and finally F orbital also undergoes screening from all the other orbitals.  Hence the F block elements are generally big in size with less nuclear charge acting on their outermost electrons.

Learn more about order of screening

In a given shell the order of screening effect is

a) s > p > d > f

b) s > p > f > d

c) f > d > p > s

d) f > p > s > d

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