Question

Factorise (x) square -3(x)square -x+3​

Answer 1

Step-by-step explanation:

${x}^{2} - 3{x}^{2} - x + 3$

$- 2 {x}^{2} - x + 3 = 0 \\ \\ - (2 {x}^{2} + x - 3) = 0$

$2 {x}^{2} + x - 3 = 0 \\ 2 {x}^{2} + (3 - 2)x - 3 = 0 \\ 2 {x}^{2} + 3x - 2x - 3 = 0</p><p>$

$x(2x + 3) - 1(2x + 3) = 0 \\ (2x + 3)(x - 1) = 0$

x=1

x=-3/2