Question

factorise X square + X upon 4 minus 1 upon 8

Answer 1

${x}^{2} + \frac{x}{4} - \frac{1}{8} = \\ 8{x}^{2} + 2x - 1 = \\ 8 {x}^{2} + 4x - 2x - 1 = \\ 4x(2x + 1) - (2x + 1) = \\ (4x - 1) \times (2x + 1)$