factorise x(x + 1)(x + 2)(x + 3) - 8
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x(x + 1)(x + 2)(x + 3) - 8
=( x² + x ) (x² + 5x + 6 ) - 8
= x²( x² + 5x + 6) + x ( x² + 5x + 6) - 8
= x⁴ + 5x³ + 6x² + x³ + 5x² + 6x - 8
= x⁴ + 5x³ + x³ + 6x² + 5x² + 6x - 8
= x⁴ + 6x³ + 11x² + 6x - 8
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