Factorise x(x^3-y^3)+3xy(x-y)
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Answer:
x(x-y)[x²+xy+y²+3y]
Explanation:
x(x³-y³)+3xy(x-y)
= x(x-y)(x²+xy+y²)+3xy(x-y)
= x(x-y)[x²+xy+y²+3y]
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