factorise: x^y^2 - 2xy + 1
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x²y² - 2xy + 1
x²y² - xy - xy + 1
xy( xy - 1 ) - ( xy - 1)
( xy - 1 )( xy - 1 )
( xy - 1 )²
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Answered by
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Answer:
x²y² - 2xy + 1
x²y² - xy - xy + 1
xy( xy - 1 ) - ( xy - 1)
( xy - 1 )( xy - 1 )
( xy - 1 )²
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