factorise x-y-x^2+y^2
Answers
Answered by
172
Hey!
The given equation= x-y-x^2+y^2.
=> (x-y)-(x^2-y^2)
Use the identity, a^2-b^2= (a-b)(a+b).
=> (x-y)-(x+y)(x-y)
Take x-y common
=> (x-y)(1-x-y). {Ans.}
The given equation= x-y-x^2+y^2.
=> (x-y)-(x^2-y^2)
Use the identity, a^2-b^2= (a-b)(a+b).
=> (x-y)-(x+y)(x-y)
Take x-y common
=> (x-y)(1-x-y). {Ans.}
Answered by
3
The answer is -( x + y - 1) (x - y)
Given: x - y - x² + y²
To Find: The factor of x - y - x² + y²
Solution:
Evaluate
x - y - x² + y²
Rewrite the expression
-x² + xy - xy + y² + x - y
Factor out x from the equation
-x(x - y) - xy + y² + x -y
Factor out y from the expression
-x(x - y) - y(x - y) + x - y
Factor out x - y from the expression
( - x - y + 1)(x - y)
or, -( x + y - 1) (x - y)
∴ The solution is -( x + y - 1) (x - y)
Hence the factor = -( x + y - 1) (x - y)
#SPJ2
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