Question

factorise x2+1/x2-2-3x+3/x

Answer 1

Heya!!
Here is your answer is in the pic above.




Hope it helps you.

Answer 2

Answer:

$(x-{\frac{1}{x})(x-\frac{1}{x}-3)$

Step-by-step explanation:

The given equation is:

$x^2+{\frac{1}{x^2}}-2-3x+\frac{3}{x}$

Using the identity, $(a-b)^2=a^2+b^2-2ab$, we have

$(x-\frac{1}{x})^2=x^2+{\frac{1}{x^2}-2$

Thus, the given equation becomes,

$x^2+{\frac{1}{x^2}}-2-3x+\frac{3}{x}=(x-\frac{1}{x})^2-3x+{\frac{3}{x}$

=$(x-\frac{1}{x})^2-3(x-{\frac{1}{x}})$

=$(x-{\frac{1}{x})(x-\frac{1}{x}-3)$

which is the required factorized form.