factorise x²-(√2+1)x+√2
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Hi friend!!
Given polynomial,
x²-(√2+1)x+√2
=x²-√2x-x+√2
=x(x-√2)-1(x-√2)
=(x-1)(x-√2)
So, (x-1) and (x-√2) are the factors of the given polynomial.
I hope this will help you
Given polynomial,
x²-(√2+1)x+√2
=x²-√2x-x+√2
=x(x-√2)-1(x-√2)
=(x-1)(x-√2)
So, (x-1) and (x-√2) are the factors of the given polynomial.
I hope this will help you
DhanyaDA:
Welcome :)
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3
here is the factorization friend.
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