Question

Factorise: x² – 2x – 15 using middle term splitting method​

Answer 1

Answer:

x^2 - 2x-15

 =   x^2 -5x +3x -15

=  x(x-5) + 3(x-5)

= (x+3)(x-5)

mark me brailiest

Answer 2

$\large a+b = –2$

ab = -15

1-15= -14

3-5 = -2

$\large a = –5$

$\large b = 3$

$\large (x^2</p><p> −5x)+(3x –15$

$\large x(x–5) +3(x-5)$

$\huge\star{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}⋆$

$\large \left(x-5\right)\left(x+3\right)$