factorise x²-3√5x-20
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This sum is solved by sum and product method
X^2-3\/5x-20
The sum of - 4\/5x+1\/5x=-3\/5x
The product of - 4\/5x*1\/5x= 20*x^2=20x^2
So,
X^2 +\/5x-4\/5x-20
X(x+\/5)-4\/5(x+\/5)
[taking commonly out]
(x+\/5)(x-4\/5)
(OR)
[Multiple of - 20*x^2 is - 4 root 5 x and +1 root 5 x and it's sum also gives - 3 root 5 x]
x^2-3 root 5 x-20
X^2+ root 5 x - 4 root 5 x - 20
x(x+root 5)-4 root 5(x+root 5)
(x-4 root 5)(x+root 5)
X^2-3\/5x-20
The sum of - 4\/5x+1\/5x=-3\/5x
The product of - 4\/5x*1\/5x= 20*x^2=20x^2
So,
X^2 +\/5x-4\/5x-20
X(x+\/5)-4\/5(x+\/5)
[taking commonly out]
(x+\/5)(x-4\/5)
(OR)
[Multiple of - 20*x^2 is - 4 root 5 x and +1 root 5 x and it's sum also gives - 3 root 5 x]
x^2-3 root 5 x-20
X^2+ root 5 x - 4 root 5 x - 20
x(x+root 5)-4 root 5(x+root 5)
(x-4 root 5)(x+root 5)
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