Question

factorise x²+4x+4-y²​

Answer 1

Answer:

sorry don't know the answer

Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

To Factorize:

• x²+4x+4-y²

Solution:

$:\longrightarrow x^2 + 4x + 4 - y^2 \\:\implies [(x)^2 + 2(x)(2) + (2)^2] - y^2 \\:\implies (x + 2)^2 - y^2 \\\bf{:\implies (x + 2 + y)(x + 2 - y)}$

Formula Used:

• a^2 + 2ab + b^2 = (a+b)^2
• a^2 - b^2 = (a+b)(a-b)

Learn More:

$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\bf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\bf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\bf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) - B^{3}\\\\8)\bf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9)\bf\: A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\ \end{minipage}}$