Question

factorise x²+4x-5 by using factor theorem​

Answer 1

Step-by-step explanation:

${x}^{2} + 4x - 5 = 0$

${x}^{2} + 5x - x - 5 = 0$

$x(x + 5) - 1(x + 5) = 0$

$(x + 5)(x - 1) = 0$

$x + 5 = 0 \: \: or \: \: x - 1 = 0$

$x = - 5 \: \: or \: \: x = 1$

Therefore 1and-5are the root of equation

I hope you will practice it.