Factorise (x²-4x) (x²-4x - 1) - 20.
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Factorise (x²-4x) (x²-4x - 1) - 20
Good question,
Here is your perfect answer!
(x²-4x) (x²-4x - 1) - 20
= (x² - 4x)² - (x² - 4x) - 20
Let x²- 4x be y.
= y² - y - 20
= y² - 5y + 4y - 20
= y(y-5) + 4(y-5)
= (y+4) (y-5)
Put y = x² - 4x,
= (x² - 4x +4) (x² - 4x - 5)
Factorise both by middle term splitting method,
= (x-2)(x-2) (x-5)(x+1)
Good question,
Here is your perfect answer!
(x²-4x) (x²-4x - 1) - 20
= (x² - 4x)² - (x² - 4x) - 20
Let x²- 4x be y.
= y² - y - 20
= y² - 5y + 4y - 20
= y(y-5) + 4(y-5)
= (y+4) (y-5)
Put y = x² - 4x,
= (x² - 4x +4) (x² - 4x - 5)
Factorise both by middle term splitting method,
= (x-2)(x-2) (x-5)(x+1)
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ayanf123
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Factorise (x²-4x) (x²-4x - 1) - 20.
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Factorise (x²-4x) (x²-4x - 1) - 20
Good question,
Here is your perfect answer!
(x²-4x) (x²-4x - 1) - 20
= (x² - 4x)² - (x² - 4x) - 20
Let x²- 4x be y.
= y² - y - 20
= y² - 5y + 4y - 20
= y(y-5) + 4(y-5)
= (y+4) (y-5)
Put y = x² - 4x,
= (x² - 4x +4) (x² - 4x - 5)
= (x² - 2x - 2x +4) (x² - 5x + x - 5)
= (x-2)² (x+1)(x-5)
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