Question

factorise x2+4y2-4xy-9z2​

Answer 1

Answer:

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Answer 2

Answer:

Factorise x2+4y2-4xy-9z2​

Step-by-step explanation:

$x^{2} +4y{2} -4xy-9z^{2}$

from this equation we can write:

$(x^{2} +4y^{2} -4xy)-9z^{2}$

[$x^{2} +(2y)^{2} -$(2×x×2y)]-$9z^{2}$

we get

$(x-2y)^{2} -9z^{2}$ by using the equation ($a-b)^{2} =a^{2}+b^{2} -2ab$

      =$(x-2y)^{2} -(3z)^{2} \\(x-2y-3z)(x-2y+z)$ by using the equation$a^{2} -b^{2} =(a-b)(a+b)$

so,

the answer is $(x-2y-z)(x-2y+z)$