factorise
x²+5x+4 and find the zeros.....
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Answered by
0
plz see the attachment of
factoring x²+5x+4 and find the zeros...
hope this will help.
factoring x²+5x+4 and find the zeros...
hope this will help.
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Agush:
It can also be solved using quadratic formula and completing square
Answered by
1
Hi friend,
x²+5x+4 = 0
x²+x+4x+4 = 0
x(x+1)+4(x+1) = 0
(x+1)(x+4) = 0
x+1 = 0 ; x = -1
x+4 = 0 ; x = -4
Therefore, the zeroes of the given polynomial are -1 and -4.
Check:-
→ (-1)²+5(-1)+4
= 1-5+4
= 5-5
= 0
→ (-4)²+5(-4)+4
= 16-20+4
= 20-20
= 0
Hence verified.
Hope it helps
x²+5x+4 = 0
x²+x+4x+4 = 0
x(x+1)+4(x+1) = 0
(x+1)(x+4) = 0
x+1 = 0 ; x = -1
x+4 = 0 ; x = -4
Therefore, the zeroes of the given polynomial are -1 and -4.
Check:-
→ (-1)²+5(-1)+4
= 1-5+4
= 5-5
= 0
→ (-4)²+5(-4)+4
= 16-20+4
= 20-20
= 0
Hence verified.
Hope it helps
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