Factorise x² + 6x - 16 = 0
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Answered by
74
hey, here is your answer.......
x^2 + 6x - 16 = 0.........
x^2 + 8x - 2x - 16 = 0..........
x [x + 8] -2[x + 8] = 0.........
(x+8)(x-2) = 0..........
Therefore, x = 2 (or) x = -8..........
hope this helps you......
thank you.....
plzz mark me as brainliest.......
x^2 + 6x - 16 = 0.........
x^2 + 8x - 2x - 16 = 0..........
x [x + 8] -2[x + 8] = 0.........
(x+8)(x-2) = 0..........
Therefore, x = 2 (or) x = -8..........
hope this helps you......
thank you.....
plzz mark me as brainliest.......
Answered by
10
Given,
The expression: x² + 6x - 16 = 0.
To find,
The factors of the given expression.
Solution,
We can easily solve this expression by following the given steps.
According to the question,
We have the following expression:
x² + 6x - 16 = 0
Now, we can factorise it by splitting the middle term into two terms such that their subtraction will give 6x and multiplication will give -16x².
These two terms are 8x and -2x.
x²+8x-2x-16 = 0
Taking x common from the first two terms and -2 common from the last two terms:
x(x+8)-2(x+8) = 0
Taking (x+8) as a common factor:
(x+8)(x-2) = 0
Hence, the factors of x² + 6x - 16 = 0 are (x+8)(x-2).
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