Question

Factorise:
x²+6x+8

x²-7x+12​

Answer 1

Answer:

$\red{Given \: that : }$

$\green{ {x}^{2} + 6x + 8}$

$\red{split \: middle \: term : }$

$\green{ {x}^{2} + 4x + 2x + 8}$

$\red{ group \: pair \: of \: terms : }$

$\green{ ({x}^{2} + 4x) +( 2x + 8)}$

$\red{factor \: each \: binomials :}$

$\green{ x(x + 4)+ 2(x + 4)}$

$\red{factor \: out \: common \: factor \:(x + 4) }$

$\green{( x+ 2)(x + 4)}$

${ \red{hence \: factors \: of \: {x}^{2} + 6x + 8 \: are \: }}$

$\huge {\boxed{ \green{ (x+ 2)(x + 4)}}}$

$\pink{Given \: that : }$

$\blue{ {x}^{2} + 7x + 12}$

$\pink{split \: middle \: term : }$

$\blue{ {x}^{2} + 3x + 4x + 12}$

$\pink{ group \: pair \: of \: terms : }$

$\blue{ ({x}^{2} + 3x) +( 4x + 12)}$

$\pink{factor \: each \: binomials :}$

$\blue{ x(x + 3)+ 4(x + 12)}$

$\pink{factor \: out \: common \: factor \:(x + 3) }$

$\blue{( x+ 3)(x + 4)}$

${ \pink{hence \: factors \: of \: {x}^{2} + 7x + 12 \: are \: }}$

$\huge {\boxed{ \blue{ (x+ 3)(x + 4)}}}$

Step-by-step explanation:

Hope this helps you ✌️