Question

factorise
( x2 - 6x2) - 8(x2 - 6x + 8 ) - 64​

Answer 1

Answer:

step by step explanation :

(x²-6x)²-8(x²-6x+8)-64

put,

x²-6x=m

m²-8(m+8)-64

m²-8m-64-64

m²-8m-128

m(m-16) 8(8-16)

(m-16) (m+8)

Resubstitue the value m :

(x²-6x-16) (x²-6x+18)

(x²-8x+2x-16) (x²-4x-2x+8)

[x(x-8)+2(x-8)] [x(x-4)-2(x-4)]

(x-8) (x-2) (x+2) (x-4)