Question

Factorise x2 - 9x + 8 by factor theorem.​

Answer 1

${x}^{2} - 9x + 8 = 0$

${x}^{2} - x - 8x + 8 = 0$

$x(x - 1) - 8(x - 1) = 0$

$(x - 1)(x - 8) = 0$

$x = 1 \: \: and \: \: \: \: x = 8$

therefore the factor of x in this equation is 8 and 1.

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Answer 2

Step-by-step explanation:

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