Question

factorise x²-x-12
what is the answer ​

Answer 1

Answer:

$ax {}^{2} + bx + c = 0 \\ a =+1 {}^{2} \\ b = -1 \\ c = -12$

$x {}^{2} - x - 12 = 0 \\ x {}^{2} - 4x + 3x - 12 \\ x(x - 4) + 3(x - 4) \\ ( x - 4)(x + 3)$

$x - 4 = 0 \: \\ x = 0 + 4 \\ x = 4$

$x + 3 = 0 \\ x = 0 - 3 \\ x = - 3$

ok ok friends✌✌✌✌✌✌✌

Answer 2

Step-by-step explanation:

ax

2

+bx+c=0

a=+1

2

b=−1

c=−12

\begin{gathered}x {}^{2} - x - 12 = 0 \\ x {}^{2} - 4x + 3x - 12 \\ x(x - 4) + 3(x - 4) \\ ( x - 4)(x + 3)\end{gathered}

x

2

−x−12=0

x

2

−4x+3x−12

x(x−4)+3(x−4)

(x−4)(x+3)

\begin{gathered}x - 4 = 0 \: \\ x = 0 + 4 \\ x = 4\end{gathered}

x−4=0

x=0+4

x=4

\begin{gathered}x + 3 = 0 \\ x = 0 - 3 \\ x = - 3\end{gathered}

x+3=0

x=0−3

x=−3