Factorise x²+y²+2(xy+xz+yz)
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X²+y²+2(xy-yz-zx)
x²+y²+2xy-2yz-2zx
(x²+y²+2xy)-(2yz+2zx)
(x+y)²-2z(y+x). (x²+y²+2xy = (x+y)² )
taking (x+y) common
(x+y)(x+y-2z)
hope this helps
x²+y²+2xy-2yz-2zx
(x²+y²+2xy)-(2yz+2zx)
(x+y)²-2z(y+x). (x²+y²+2xy = (x+y)² )
taking (x+y) common
(x+y)(x+y-2z)
hope this helps
Anonymous:
ohh! there is - not +
Answered by
4
So the answer is
(x+y+2z) (x+y)
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