factorise: x2-y2-2x+6y-8
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Answered by
3
2x-2y-2x+6y-8
=2x-2x-2y+6y-8
=4y-8
=4(y-2)
=2x-2x-2y+6y-8
=4y-8
=4(y-2)
Answered by
8
x²-2x -y²+6y -8
=x²-2x +1 -y² +6y -9
=(x+1)² - (y² -6y +3²)
=(x-1)²-(y-3)²
=[(x-1) + (y-3)][(x-1) - (y-3)]
=(x+y-4)(x-y+2)
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