Question

Factorise : x3+13x2+32x+20.​

Answer 1

Answer:

( + 1 )( +2 ) ( + 1 0 )

Step-by-step explanation:

Question Factorise: x3 + 13x2 + 32x + 20

Solution:

Let p(x) = x3 + 13x2 + 32x + 20

p(-1) = -1 + 13 - 32 + 20 = -33 + 33 = 0

Therefore (x + 1) is a factor of p(x).

On dividing p(x) by (x + 1) we get

p(x)   (x + 1) = x2 + 12x + 20

Thus,

x3 + 13x2 + 32x + 20 = (x + 1)(x2 + 12x + 20)

= (x + 1) (x2 + 10x + 2x + 20)

= (x + 1)[x(x + 10) + 2(x + 10)]

= (x + 1) (x +2) (x + 10)

Hence, x3 + 13x2 + 32x + 20 = (x + 1) (x +2) (x + 10).

Answer 2

Answer:

The value of x 3 +13x 2 +32x+20 is

x³+ x²+ 12x² +1x +20x +20

=x² (x+1) +12x(x+1) +20 (x+1)

=(x−1) (x² +12x+20)

=(x−1) (x² + 10x +2x +20)

=(x+1) [x(x+10) +2 (x +10)]

=(x+1) (x+2) (x+10)..Ans..