Question

Factorise x3 - 18x2 + 99x - 162, using factor
theorem.

Answer 1

Answer:

3,6,9

Step-by-step explanation:

by trail and error method

we can find 3 is one of the root

so one factor is (x-3)

so divide the equation with x-3

and you will get

= x²-15x+54

=x² -6x-9x+54

=x(x-6) -9(x-6)

=(x-6)(x-9)

so the roots are

3,6,9

Answer 2

Answer: Hey buddy here's ur answer

Taking x as λ we get :

Step-by-step explanation:f(λ) = λ³ - 18λ² + 99λ - 162 = 0

Now f(3) = 3³ - 18(3)² + 99(3) - 162

= 27 - 162 + 297 - 162

= 324 - 324

= 0

By the factor theorem (λ - 3) is a factor of f(λ)

Use short division

λ³ - 18λ² + 99λ - 162 = (λ - 3)(λ² - 15λ - 54)

= (λ - 3)(λ - 6)(λ - 9)

Hence

(λ - 3)(λ - 6)(λ - 9) = 0

Plzz mark as the brainliest.