Question

Factorise : x³ – 23x² + 142x -120 *

Answer 1

${x}^{3} - 23 {x}^{2} + 142x - 120$

$= {x}^{3} - {x}^{2} - 22 {x}^{2} + 22x + 120x - 120$

$= {x}^{2} (x - 1) - 22x(x - 1) + 120(x - 1)$

$= ( {x}^{2} - 22x + 120)(x - 1)$

$= ( {x}^{2} - 12x - 10x + 120)(x - 1)$

$= (x(x - 12) - 10(x - 12))(x - 1)$

$= (x - 1)(x - 10)(x - 12)$

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