Question

factorise
X³-23x²+142x-120​

Answer 1

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• Factorise ${x}^{3} - 23 {x}^{2} + 142x - 120$

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${x}^{3} - 23 {x}^{2} + 142x - 120$

$= {x}^{3} - {x}^{2} - 22 {x}^{2} + 22x + 120 - 120$

$= {x}^{2} (x - 1) - 22x(x - 1) + 120(x - 1)$

$= (x - 1)( {x}^{2} - 22x + 120)$

$= (x - 1)( {x}^{2} - 12x - 10x+ 120)$

$= (x - 1)( x(x - 12) - 10(x - 12))$

$= (x - 1)(x - 10)(x - 12)$

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• $(x - 1)(x - 10)(x - 12)$

Answer 2

Answer:

I hope it helped u...