Question

factorise
x3-2x2y+3xy2-6y3
​

Answer 1

Answer:

Step-by-step explanation:

→ 3x-2×2xy+3×2xy-6×3y

→ 3x+2xy-18y

Answer 2

Answer:

Here is your Answer....

${x}^{3} - 2 {x}^{2}y + 3x {y}^{2} - 6 {y}^{3} = 0\\ {x}^{2} (x - 2y) + 3 {y}^{2}(x - 2y) = 0 \\ (x - 2y)( {x}^{2} + 3 {y}^{2} ) = 0$

Hope it helps you.........

:-)