factorise x3-3x2-9x-5
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Answer:
X³ - 3x² - 9x - 5
= x³ + x² - 4x² - 4x - 5x - 5
= x²( x + 1) - 4x ( x + 1) - 5(x + 1)
= (x + 1)(x² - 4x - 5)
= (x + 1)(x² -5x + x - 5)
= (x + 1)(x - 5) (x + 1)
hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .
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