The perimeter of the isosceles right triangle is 2p then it's area
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Best Answer: The ratio of the sides of an isosceles right triangle is: 1 : 1 : √ 2 , due to
the Pythagorean Theorem. The perimeter (P) is:
P = 1x + 1x + (√ 2)x = (2 + √ 2)x = 2p ... solve for "x"
x = 2p ⁄ (2 + √ 2)
... where "x" is the scale factor AND in this case it also happens to be the
... length of each of the two identical sides "1x"
The area then is: A = (½) • b • h
= (½) • (1x) • (1x)
= x² ⁄ 2 ... replace "x"
= [ 2p ⁄ (2 + √ 2) ]² ⁄ 2
= 2p² ⁄ (2 + √ 2)²
= 2p² ⁄ (4 + 4√ 2 + 2)
= 2p² ⁄ (6 + 4√ 2)
= p² ⁄ (3 + 2√ 2) ... area
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