factorise
x³-3x²-9x-5
Answers
Answered by
11
Answer:
(x-5)(x+1)2
Step-by-step explanation:
x=x²2(x-5)+2x(x-5)+(x-5)
(x-5)(x²2+2x+1)
(x-5)(x+1)2
Answered by
2
Step-by-step explanation:
Given :
A polynomial x^3 - 3x^2 - 9x - 5
To Find :
Three factors of polynomial x^3 - 3x^2 - 9x - 5
Solution :
Constant Term = -5
Factors of Constant Term = 1,5
Putting x = 1 :
→ (1)^3 - 3(1)^2 - 9(1) - 5
→ 1 - 3 - 9 - 5
→ 1 - 17
→ - 16
Putting x = -1 :
→ (-1)^3 - 3(-1)^2 -9(-1) - 5
→ - 1 - 3 + 9 - 5
→- 4 + 9 - 5
→5 - 5
→ 0
- x = -1 is the root .
- x + 1 is the factor.
(Refer to the attachment)
Now :
→ x^2 - 4x - 5
→ x^2 - (5x - 1x) - 5
→ x^2 - 5x + 1x - 5
→x(x - 5) + 1(x - 5)
→ (x + 1)(x - 5)
So , The three factors are (x+1) , (x-5) , (x+1)...
Attachments:
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