Question

factorise x3 - 5x2 + x - 5 ​

Answer 1

Answer:

f(1)= 1-5-1+5 =0

(x-1) is a factor

f(-1)= (-1)^3-5(-1)^2 --(-1) +5 =—-1- 5+1+5 =0

( x+1) is a factor

f(5)= (5 )^3--(5) 5^2 --( 5 ) +5= 125 -1 25—-5+5 =0

( x-- 5) is a factor

Factors of the given problem is( x+1)(x-1) (x-5)

Answer 2

Answer:

$({x}^{2} + 1)(x - 5)$

Step-by-step explanation:

Here we will use

${x}^{2} - {y}^{2} = (x + y)(x - y)$

therefore substituting values , we get

${x}^{2} (x - 5) + 1(x - 5)$

$( {x}^{2} + 1)(x - 5)$