factorise x³-6x²+11x-6
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Factorise : ( x³ - 6x² + 11x - 6 )
We have,
x³ - 6x² + 11x - 6
= x³ - (3+3)x² + (9+2)x - 6
= x³ - 3x² - 3x² + 9x + 2x - 6
= x³ - 3x² + 2x - 3x² + 9x - 6
= x ( x² - 3x + 2 ) - 3 ( x² - 3x + 2 )
= (x - 3)(x² - 3x + 2)
= (x - 3)(x² - 2x - x + 2)
= (x - 3)[ x(x-2) - 1(x-2) ]
= (x - 3)[ (x - 1) (x - 2) ]
= (x - 1)(x - 2)(x - 3)
Thank You!
______^^_
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