Question

Factorise x³ +7x +6​

Answer 1

Answer:

$let \: p(x) = {x}^{3} + 7 + 6 \\ we \: have p(1)=0 \\ Thus, (x−1) is \: a \: factor of p(x). \\ The \: other \: factor \: is \:  x {}^{2} +x−6 = (x+3)(x−2)</p><p></p><p> \\ Therefore, x {}^{2} −7x+6=(x−1)(x+3)(x−2)</p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p>$

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