Question

Factorise x4y12- x12y4

Answer 1

Hope u like my process
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${x}^{4} {y}^{12} - {x}^{12 } {y}^{4} \\ \\ = {x}^{4} {y}^{4} ( {y}^{8} - {x}^{8} ) \\ \\ = {x}^{4} {y}^{4} ( {( {y}^{4} )}^{2} - {( {x}^{4}) }^{2} ) \\ \\ = {x}^{4} {y}^{4} ( {y}^{4} - {x}^{4} )( {y}^{4} + {x}^{4} ) \\ \\ = {x}^{4} {y }^{4} ( {x}^{4} + {y}^{4} )( {( {y}^{2} )}^{2} - { ({x}^{2}) }^{2} ) \\ \\ = {x}^{4} {y}^{4} ( {x}^{4} + {y}^{4} )( {x}^{2} + {y}^{2} )( {y}^{2} - {x}^{2} ) \\ \\ = {x}^{4} {y}^{4} ( {x}^{4} + {y}^{4} )( {x}^{2} + {y}^{2} )(x + y)(y - x)$
Hope this is ur required answer

Proud to help you

Answer 2

Answer:

Hope it is correct.

THANK YOU

Step-by-step explanation:

Do it by using the identity