Question

Factorise x⁴y⁴-xy........​

Answer 1

 x⁴y⁴-xy

=  (xy)⁴-xy

=I(  xy^2)I^2-xy

Answer 2

Answer:

$xy(xy-1)(x^2y^2+1)$

Step-by-step explanation:

$x^4y^4-xy \\=> xy(x^3y^3-1)$

Now, using the idenitity $a^3-b^3=(a-b)(a^2+ab+b^2)$, we get -

$=> xy(xy-1)(x^2y^2+xy+1)$