Question

factorise x⁸-1
points points points​

Answer 1

Answer:

$\huge\fbox\colorbox{pink}{✿Yøur-An˜swer♡}$(x⁴+1) (x²+1) (x+1) (x-1)x⁸-1=(x⁴)²-(1)²

=(x⁴+1) [(x²)²-(1)²]

=(x⁴+1) (x²+1) (x²-1)

=(x⁴+1) (x²+1) (x²-1²)

=(x⁴+1) (x²+1) (x+1) (x-1)

$\huge\color{pink}{°•✩shravyanb✩°•}$

Answer 2

(x⁴+1) (x²+1) (x+1) (x-1)x⁸-1=(x⁴)²-(1)²

x⁴+1) (x²+1) (x+1) (x-1)x⁸-1=(x⁴)²-(1)²=(x⁴+1) [(x²)²-(1)²]

x⁴+1) (x²+1) (x+1) (x-1)x⁸-1=(x⁴)²-(1)²=(x⁴+1) [(x²)²-(1)²]=(x⁴+1) (x²+1) (x²-1)

x⁴+1) (x²+1) (x+1) (x-1)x⁸-1=(x⁴)²-(1)²=(x⁴+1) [(x²)²-(1)²]=(x⁴+1) (x²+1) (x²-1)=(x⁴+1) (x²+1) (x²-1²)

x⁴+1) (x²+1) (x+1) (x-1)x⁸-1=(x⁴)²-(1)²=(x⁴+1) [(x²)²-(1)²]=(x⁴+1) (x²+1) (x²-1)=(x⁴+1) (x²+1) (x²-1²)=(x⁴+1) (x²+1) (x+1) (x-1)

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