Question

factorise xcube-xsquare+ax+x-a-1​

Answer 1

Answer:

x³-x²+ax+x-a-1 = (x-1)(x²+a+1)

Step-by-step explanation:

Given x³-x²+ax+x-a-1

Rearranging the terms , we get

= x³-x²+ax-a+x-1

= x²(x-1)+a(x-1)+1(x-1)

= (x-1)(x²+a+1)

Therefore,

x³-x²+ax+x-a-1 = (x-1)(x²+a+1)

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Answer 2

(x - 1) (x² + a + 1)

Step-by-step explanation:

Given,

x³ - x² + ax + x - a - 1

Arranging the expressions:

x³ - x² + ax - a + x - 1

Taking out x² as the common:

x² (x - 1) +  ax - a + x - 1

Taking out a as the common:

x² (x - 1) +  a(x - 1) + x - 1

Taking out 1 as the common:

x² (x - 1) +  a(x - 1) + 1(x - 1)

Taking out (x - 1) as the common:

(x - 1) (x² + a + 1)

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