Math, asked by simranlulla289, 10 months ago

Factorise:(y^2-3y)^2-5(y^2-3y)-50

Answers

Answered by ayushiashok
36

Answer:

(y2-3y+5)(y2-3y+10)

Step-by-step explanation:

let y2-3y be x, then,

x2-5x-50

=x2-10x+5x-50

=x(x-10)+5(x-10)

=(x+5)(x-10)

now out the value:y2-3y= x

(y2-3y+5)(y2-3y+10)

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Answered by Anonymous
11

Answer:

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hey mate please refer to the attachment

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