Factorise : y (2y+5) - 3
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the answer is 2y^2+5y-3
= 2y^2+6y-y-3
= 2y(y+3)-1(y+3)
=(2y-1)(y+3)
= 2y^2+6y-y-3
= 2y(y+3)-1(y+3)
=(2y-1)(y+3)
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