Question

Factorise y^3+23y^2+142y-120

Answer 1

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Answer 2

Answer:

(y-1)(y-10)(y-12)

Step-by-step explanation:

=y³–y²–22y²+22y+120y–120

=y²(y–1)–22y(y–1)+120(y–1)

=(y–1)(y²–22y+120)

=(y–1) [ y²–10y–12y+120 ]

=(y–1) [ y(y–10)–12(x–10)]

=(y–1)(y–10)(y–12)